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How To Fix UJA_EXCEPTION225 - Detected duplicate member ID '&1'


UJA_EXCEPTION225 - Overview

  • Message type: E = Error

  • Message class: UJA_EXCEPTION - BPC: Admin exception message class

  • Message number: 225

  • Message text: Detected duplicate member ID '&1'

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  • Self-Explanatory Message

    Since SAP believes that this specific error message is 'self-explanatory,' no more information has been given.The majority of messages in the SAP system have a message text, however this is frequently insufficient to comprehend or resolve the problem.

    To make things easier, more detailed information is frequently added to describe the issue, how to fix it, and the necessary steps or configuration modifications.

    Unfortunately, there isn't any extra information in this error notice.



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    You can also try searching the SAP support portal (support.sap.com) but you need a special user ID to access it. It is possible that an SAP support note exists that provides additional details about the mistake or even steps for fixing it.


UJA_EXCEPTION225 - Details

  • The SAP error message UJA_EXCEPTION225, which indicates "Detected duplicate member ID '&1'", typically occurs in the context of SAP BW (Business Warehouse) or SAP BPC (Business Planning and Consolidation) when there are duplicate member IDs in a hierarchy or dimension. This can happen during data loading, modeling, or when trying to create or modify dimensions.
    
    Cause: Duplicate Member IDs: The primary cause of this error is the presence of two or more members in a dimension or hierarchy that have the same ID. This can occur due to: Incorrect data loading processes. Manual entry errors when creating members. Issues in the source data that lead to duplicates. Data Model Issues: If the data model is not properly designed or if there are inconsistencies in the data source, it can lead to duplicate entries. Hierarchy Configuration: If you are working with hierarchies, the error may arise from incorrect configuration or updates to the hierarchy that introduce duplicates.
    Solution: Identify Duplicates:

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