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Message type: E = Error
Message class: KE -
Message number: 610
Message text: No se ha creado ning.índice secundario &2 p.tabla &1 en la base de datos
The secondary index &V2& for table &V1& improves the performance of
various functions in Profitability Analysis. However, table &V1&
already contains data, which means that it may take a long time to
create the index.
Consequently, the index has not been created in the database system.
All functions of Profitability Analysis can still be carried out, even
without the index.
If the index does not exist in the database system, you receive a
dialog box whenever you execute a function that calls for the index. If
you are not satisfied with the runtime of that function, create the
index in the database system.
To do so:
Call up transaction SE11, enter database table "&V1&" and choose
"Display".
On the next screen, choose:
"Goto" -> "Indexes"
The system displays all the secondary indexes for table &V1&. Select
index &V2&.
Choose the "Display <-> Change" icon.
Select "Index for all database systems" and activate the index again.
Extracto de mensaje de error del sistema SAP. Copyright SAP SE.
KE610
- No se ha creado ning.índice secundario &2 p.tabla &1 en la base de datos ?Get instant SAP help. Start your 7-day free trial now.
KE609
Para la tabla &1 ya existe un índice secundario &2
¿Qué causa este problema? An active secondary indexs (&V2&) already exist for table &V1&.Respuesta del sistema No new index was cr...
KE608
Se ha activado el índice secundario &2 para la tabla 1&
Mensaje autoexplicativo Dado que SAP cree que este mensaje de error específico 'se explica por sí mismo', no se ha proporcionado más información. ...
KE611
Activado índice secundario &2 para tabla &1 con mensajes de advertencia
¿Qué causa este problema? Secondary index &V2& was activated for table &V1&. However, a situation occurred which could lead to an e...
KE612
No se ha activado índice secundario &2 para tabla &1
¿Qué causa este problema? Errors occurred when the system tried to activate secondary index &V1& for table &V2&.Respuesta del siste...
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